5t^2-17t+20=0

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Solution for 5t^2-17t+20=0 equation:


Simplifying
5t2 + -17t + 20 = 0

Reorder the terms:
20 + -17t + 5t2 = 0

Solving
20 + -17t + 5t2 = 0

Solving for variable 't'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
4 + -3.4t + t2 = 0

Move the constant term to the right:

Add '-4' to each side of the equation.
4 + -3.4t + -4 + t2 = 0 + -4

Reorder the terms:
4 + -4 + -3.4t + t2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -3.4t + t2 = 0 + -4
-3.4t + t2 = 0 + -4

Combine like terms: 0 + -4 = -4
-3.4t + t2 = -4

The t term is -3.4t.  Take half its coefficient (-1.7).
Square it (2.89) and add it to both sides.

Add '2.89' to each side of the equation.
-3.4t + 2.89 + t2 = -4 + 2.89

Reorder the terms:
2.89 + -3.4t + t2 = -4 + 2.89

Combine like terms: -4 + 2.89 = -1.11
2.89 + -3.4t + t2 = -1.11

Factor a perfect square on the left side:
(t + -1.7)(t + -1.7) = -1.11

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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